How much amount should be added to 200cc of seminormal solution of NAOH to make it exactly decinormal?
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Answered by
125
helllo.....
Normality (N1) = 0.5 (seminormal)
Volume(V1) = 200 cc
Normality (N2) = 0.1 (decinormal)
Volume (V2) = ?
(N1)(V1) = (N2) (V2)
0.5 X 200 = 0.1 X (V2)
(V2) = 1000 ml
Volume of water added = 1000 -200 = 800 ml
thank you.... ☺
Normality (N1) = 0.5 (seminormal)
Volume(V1) = 200 cc
Normality (N2) = 0.1 (decinormal)
Volume (V2) = ?
(N1)(V1) = (N2) (V2)
0.5 X 200 = 0.1 X (V2)
(V2) = 1000 ml
Volume of water added = 1000 -200 = 800 ml
thank you.... ☺
Answered by
33
Answer:
it's answer is 800ml...........
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