Question

how much bacl2 is required to react with 10 gram Fe2(So4)3 the formula masses are Fe2(So4)3 399.88 and 208.4 for bacl2

Answer 1

Answer:

volume Fe2(SO4)3 x conversion factor x Fe2(SO4)3 molarity = moles Fe2(SO4)3

moles Fe2(SO4)3 x (mole-to-mole ratio) = moles BaSO4

moles x molar mass=grams

Determine reactants and products

Reactants are: BaCl2 (aq) and Fe2(SO4)3 (aq)

Products are: BaSO4 and FeCl3

Use Solubility Rules (Table 4.1) to determine physical states of the products

BaSO4 (s) <-insoluble and FeCl3 (aq) <- soluble

Write the reaction

BaCl2 (aq) + Fe2(SO4)3 (aq) -> BaSO4 (s) + FeCl3 (aq)

Balance the reaction

3 BaCl2 (aq) + Fe2(SO4)3 (aq) -> 3 BaSO4 (s) + 2 FeCl3 (aq)

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