How much bacl2 would be needed tomake 250ml of a solution having same concentration of cl- ions as one containing 3.78 gm of nacl per 100ml of the solution?
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Let's take the case of NaCl.
NaCl->Na+ + Cl-
[Cl-]=[NaCl]=3.78*1000/58.5*100=?
{Molarity=weight(in g)*1000/Mol.mass(in g/mol)*volume}
Now, BaCl2.
BaCl2->Ba2+ + 2Cl-
[Cl-]=?
[BaCl2]=[Cl-]/2=?
[Cl-]=w*1000/208.3*250
{Mol. mass of BaCl2=208.3, Ba=137.3, Cl=35.5}
w=[Cl-]*208.3*250/1000=?
NaCl->Na+ + Cl-
[Cl-]=[NaCl]=3.78*1000/58.5*100=?
{Molarity=weight(in g)*1000/Mol.mass(in g/mol)*volume}
Now, BaCl2.
BaCl2->Ba2+ + 2Cl-
[Cl-]=?
[BaCl2]=[Cl-]/2=?
[Cl-]=w*1000/208.3*250
{Mol. mass of BaCl2=208.3, Ba=137.3, Cl=35.5}
w=[Cl-]*208.3*250/1000=?
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