Question

How much CaO will be produced by decomposition of 5g CaCO3

Answer 1

Given :

Decomposition of CaCO$_{3}$ is taking place.

To Find :

CaO produced by the decomposition of 5g CaCO$_{3}$

Solution :

CaCO$_{3}$ ----------> CaO + CO$_{2}$

100 g                   56 g       44 g

100 g of CaCO$_{3}$ produces 56 g of CaO

5 g of CaCO$_{3}$ will produce $\frac{56}{100} * 5$

                                          = 2.8 g of CaO

∴  2.8 grams of CaO will be produced by the decomposition of 5g CaCO$_{3}$.

Answer 2

The decomposition of calcium carbonate(CaCO₃) in presence of heat releases calcium oxide(CaO) and carbon dioxide(CO₂).

The balanced chemical equation for the decomposition of calcium carbonate(CaCO₃) will be:

$CaCO_{3} \rightarrow CaO +CO_{2}$

Given,

The amount of calcium carbonate(CaCO₃)= 5g

Number of moles of calcium carbonate(CaCO₃)=

$\frac{given\ mass}{molar\ mass} =\frac{5}{100} =0.05$

From the above reaction, 1 mole of calcium carbonate(CaCO₃) gives 1 mole of

calcium oxide(CaO).

Hence, 0.05 moles of calcium carbonate(CaCO₃) gives 0.05 mole of

calcium oxide(CaO).

One mole of calcium oxide(CaO) weighs 56g.

0.05 mole of calcium oxide(CaO) weighs 2.8g.

Hence, the decomposition of 5g of calcium carbonate(CaCO₃) gives 2.8g of calcium oxide(CaO).