how much compound interest is earned by investing rupees 20,000 for 6years at 5% per annum compounded annualy
Answers
Answered by
5
p=20000
n=6 yrs
r=5
A= p (1+r/100)n
= 20000 (1+5/100)6
=20000 (105/100)6
=20000×1.3400956
=26801.91
CI= A-P
=26801.91 - 20000
=6801.91
n=6 yrs
r=5
A= p (1+r/100)n
= 20000 (1+5/100)6
=20000 (105/100)6
=20000×1.3400956
=26801.91
CI= A-P
=26801.91 - 20000
=6801.91
Answered by
5
Heya ☺
Given that
P = ₹20,000
R = 5 % p.a.
T = 6 years
Solution
When the interest is compounded annually
C.I. = {P(1+R/100)^n - 1}
= {20,000(1+5/100)^6 - 1}
= {20,000(100+5/100)^6 - 1}
= {20,000(105/100)^6 - 1}
= {20,000(21/20)^6 - 1}
= {20,000 × (8,57,66,121/6,40,00,000) - 1}
= {20,000 × (8,57,66,121 - 6,40,00,000/6,40,00,000}
= {20,000 × 2,17,66,121/6,40,00,000}
= ₹6,801.91
Thanks
Given that
P = ₹20,000
R = 5 % p.a.
T = 6 years
Solution
When the interest is compounded annually
C.I. = {P(1+R/100)^n - 1}
= {20,000(1+5/100)^6 - 1}
= {20,000(100+5/100)^6 - 1}
= {20,000(105/100)^6 - 1}
= {20,000(21/20)^6 - 1}
= {20,000 × (8,57,66,121/6,40,00,000) - 1}
= {20,000 × (8,57,66,121 - 6,40,00,000/6,40,00,000}
= {20,000 × 2,17,66,121/6,40,00,000}
= ₹6,801.91
Thanks
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