Question

how much copper will be deposit at cathode of an electrolytic cu++ ion by the passage of 2 ampere current for 60 minutes?

Answer 1

2.3689 g of copper will be deposit at cathode of an electrolytic Cu++ ion by the passage of 2A current for 60 minutes

• As we know if we pass 96500 C , 63.5/2 grams of Cu ions will get deposited.
• For the passage of 2A current for the time period of 60min implies that
• As Q=It

                Total Charge=2*60*60

• Total Deposition Copper will be given by           $\frac{2*60*60*63.5}{2*96500 }=2.3689 grams$