Chemistry, asked by ramandhundhwal52, 10 months ago

how much cu is deposited by passing a current of 5A for 45 minutes through the molten cuso4​

Answers

Answered by lokhandepiyush26
1

Answer:

4.4469 gms.  

Explanation:

Faraday's First Law of Electrolysis states that the chemical deposition due to the flow of current through an electrolyte is directly proportional to the quantity of electricity (coulombs) passed through it.  

Faraday's First and Second Laws of Electrolysis | Electrical4u  

Problem :  

Given :  

Solution = Copper Sulphate = CuSO4.  

Current passed = 5 amperes.

Time of passing the current = 45 minutes. =45×60 seconds = 2700 seconds.

Required :

Amount of Cu deposited, or mass of Cu deposited.  From the Periodic table, we find that the atomic masses of the elements involved are :  

Cu = 63. 54 ; S =32 : O= 16  

So, CuSO4 = 63.54+32+16×4 =63.54+32+64 =159.54.  

But during electrolysis, this will be split into Cu+ ions & SO4- ions.  

According to the 1st law of Electrolysis, mass of Cu deposited ,, m = zct gms, where m = mass in gms of Cu deposited.

z=electrochemical equivalent of Cu ,  

c=current in amperes, and t=time in seconds.

What is the electrochemical equivalent of copper?

The electrochemical equivalent, sometimes abbreviated Eq/z, of a chemical element is the mass of that element (in grams) transported by 1 coulomb of electric charge.  

The electrochemical equivalent of an element is measured with a voltameter. ...

Electrochemical equivalent.  

Ectrochemical equivalent of a substance may be defined as the mass of the substance deposited to one of the electrode when a current of 1 Ampere is passed for 1 Second, i.e. a quantity of electricity of one Coulomb is passed .

Element ; Electrochemical equivalent  

Copper : 0.0003294  

Hydrogen: 0.0000105  

1 more row  

Electrochemical equivalent -  

Therefore, m =zct gms ,,  

m= 00.0003294 ×5 ×2700 =4.4469 gms.  

Faraday's second law of Electrolysis :  

The Faraday constant represents the amount of electric charge carried by one mole, or Avogadro's number, of electrons.  

It is an important constant in chemistry, physics, and electronics and is commonly symbolized by the italic uppercase letter F.  

It is expressed in coulombs per mole (C/mol).

Faraday's constant can be derived by dividing the Avogadro constant, or the number of electrons per mole, by the number of electrons per coulomb.

The former is equal to approximately 6.02 x 10^ 23, and the latter is approximately 6.24 x 10 ^18. Therefore:  

F = (6.02 x 10 ^23 ) / (6.24 x 10^ 18 )= 9.65 x 10 ^4 C/mol

This calculation is accurate to three significant figures.

Both the faraday and the farad are named for Michael Faraday, one of the independent inventors of the electric motor in the early 1800s.

Answered by GUDU2003
2

Faraday's law of electrolysis.

As

W= Ite/F

F= 965900 C

t=45 x 60 sec

e for copper if taken in copper sulphate then

e= Mw.t of Salt /charge on cation

e= (63.5+96)/2

e=79.8

So

W=5 x (45 x 60) 79.8/96500

W=11.1 grams (of copper deposited on cathode or librated from anode).Faraday's law of electrolysis.

As

W= Ite/F

F= 965900 C

t=45 x 60 sec

e for copper if taken in copper sulphate then

e= Mw.t of Salt /charge on cation

e= (63.5+96)/2

e=79.8

So

W=5 x (45 x 60) 79.8/96500

W=11.1 grams (of copper deposited on cathode or librated from anode).Faraday's law of electrolysis.

As

W= Ite/F

F= 965900 C

t=45 x 60 sec

e for copper if taken in copper sulphate then

e= Mw.t of Salt /charge on cation

e= (63.5+96)/2

e=79.8

So

W=5 x (45 x 60) 79.8/96500

W=11.1 grams (of copper deposited on cathode or librated from anode).

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