Question

how much current flows through a 4kohm resistor when a potential difference of 2V is across its ends​

Answer 1

$\mathfrak{AnSwEr}$

We know that :-

V = IR

=》 $\sf{\frac{V}{R} = I}$

=》 $\sf{\frac{2}{4} = I}$

I = 1/2 A ,or, 0.5 A

Answer 2

Here Is Your Ans ⤵

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Given ⬇

resistance = 4 ohm

Potential difference = 2 v

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V = I × R ( ohm's law )

I = V / R

I = 2 / 4

I = 1 / 2

I = 0.5 Amp

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