Physics, asked by sahir3349, 1 year ago

How much current is drawn by the primary coil of a transformer which is stepdown 220 volt to 22 volt to operate a device with an impedance of 220 ohm ?

Answers

Answered by abhinav27122001
63
Here's your answer mate..
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Answered by CarliReifsteck
20

Answer:

The current is 0.01 A.

Explanation:

Given that,

Voltage in primary coil =220  V

Voltage in secondary coil = 22 V

Impedance = 220 ohm

We need to calculate the current

Using formula of power

P_{pc}=P_{sc}

E_{p}I_{p}=E_{s}I_{s}

Where, E = voltage

I = current

Put the value of current

E_{p}I_{p}=E_{s}\dfrac{E_{s}}{R_{s}}

Put the value into the formula

220\times I_{p}=\dfrac{22\times22}{220}

I_{p}=\dfrac{22\times22}{220\times220}

I_{p}=0.01\ A

Hence, The current is 0.01 A.

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