Question

how much current it s drawn by the primary coil of a transformer which steps down 220 v to 22 v to operate a device with an impedance of 220 ohm

Answer 1

Answer:

Current in secondary , i 2 = V2 / Z2 = 22 / 220 = 0.1 A

Transformation ratio , K = i 1 / i 2 = V2 / V 1

i 1 / 0.1 = 22 / 220

i 1 = 0.1 × 0.1

i 1 = 0.01 A

Current in primary coil is 0.01 A