Question

how much distance a freely falling body travels in 5 th second?​

Answer 1

Answer:

Given,

A free falling body

Distance traveled in 5s

S=ut+2/1gt²

since u=0,g=10m/s

=1/3×10×5²

=125m

Distance travelled in 5^th sis:

Distance travelled in 5s- Distance travelled in 4s

Distance travelled in 4s=1/2×10×4²

=80m

So,

s5−s4=125−80=45

Therefore,

s5−s4/s5×100

=45×125/100=36%

Answer 2

Given,

A free falling body 

Distance traveled in 5s

S=ut+21gt2 since u=0,g=10m/s

=21×10×52

=125m

Distance travelled in 5^th sis:

Distance travelled in 5s- Distance travelled in 4s

Distance travelled in 4s=21×10×42

=80m

So,

s5−s4=125−80=45

Therefore,

s5s5−s4×100=12545×100=36%