Question

how much distance the train will cover at 10 seconds if it accelerating with 4 m/s square starting from rest?​

Answer 1

Answer:

Newton first law of motion equation

$v = u + at \\ = 0 + 2 \times 10 \\ = 20 \: \frac{m}{s}$

Newton second law of motion equation

${v}^{2} - {u}^{2} = 2as \\ 400 = 2 \times4 \times s \\ s = \frac{400}{8} = 50 \: m$