how much does it cost to run one heater of 1000w and two light bulbs of 40w each for 8 hours if one unit of electricity costs Rs2
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Answered by
3
Total power required (in kWh)
P = 1000(8) + 80(8)
P = 8.640 kWh
1 kWh costs Rs.2
8.640 kWh costs 8.640X2 = Rs.17.28
Answered by
3
Power consumed by heater =1KWh
Power consumed by 2 bulbs
=40*2=80W=0.080KWh
Total power consumed
=1*8+8*0.08
=8.640KWh
Total cost of electricity
=Rs 2*8.640
=Rs 17.28
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