Question

how much electricity is required to obtain 9g of aluminium from Al³+


please do not answer from g.o.o.g.l.e​

Answer 1

Answer:

The atomic mass of Al = 27 g / mol

9g of Al =  9 / 27

​  = 0.333 moles

1 mole Al = 3 moles electrons.

0.333 moles Al = 0.333 × 3 = 1 mole electrons

1 mole electrons  = 1 faraday of electricity = 95000 C.

___________________

Hope it helps you!!

:)

Answer 2

The electricity is Aluminium are 96500 C.

Explanation:

$Al^{3+}+3e^{-}$→$Al$

The atomic mass of Al=$27g/mol$

$9g of Al= \frac{9}{27}=0.3333 moles$

1 mole Al= 3 moles electrons.

$0.333 moles Al=0.333*3=1 mole electrons$

1 mole electrons = 1 faraday of electricity =95000 C.