Solve
(3r²+ 4 x y) dx +(2x²+2 y) dy = 0.
Answers
Step-by-step explanation:
Simplifying
(2x + 2y2) * dx + (4xy + 3y2) * dy = 0
Reorder the terms for easier multiplication:
dx(2x + 2y2) + (4xy + 3y2) * dy = 0
(2x * dx + 2y2 * dx) + (4xy + 3y2) * dy = 0
Reorder the terms:
(2dxy2 + 2dx2) + (4xy + 3y2) * dy = 0
(2dxy2 + 2dx2) + (4xy + 3y2) * dy = 0
Reorder the terms for easier multiplication:
2dxy2 + 2dx2 + dy(4xy + 3y2) = 0
2dxy2 + 2dx2 + (4xy * dy + 3y2 * dy) = 0
2dxy2 + 2dx2 + (4dxy2 + 3dy3) = 0
Reorder the terms:
2dxy2 + 4dxy2 + 2dx2 + 3dy3 = 0
Combine like terms: 2dxy2 + 4dxy2 = 6dxy2
6dxy2 + 2dx2 + 3dy3 = 0
Solving
6dxy2 + 2dx2 + 3dy3 = 0
Solving for variable 'd'.
Move all terms containing d to the left, all other terms to the right.
Factor out the Greatest Common Factor (GCF), 'd'.
d(6xy2 + 2x2 + 3y3) = 0
Subproblem 1
Set the factor 'd' equal to zero and attempt to solve:
Simplifying
d = 0
Solving
d = 0
Move all terms containing d to the left, all other terms to the right.
Simplifying
d = 0
Solution :
Value of y is 25
x + y = 69
x + 25 = 69
x = 69 – 25
x = 44.
Hence :
- The value of x is 44.