Math, asked by Priyansha6283, 15 days ago

Solve
(3r²+ 4 x y) dx +(2x²+2 y) dy = 0.​

Answers

Answered by akashravat936
0

Step-by-step explanation:

Simplifying

(2x + 2y2) * dx + (4xy + 3y2) * dy = 0

Reorder the terms for easier multiplication:

dx(2x + 2y2) + (4xy + 3y2) * dy = 0

(2x * dx + 2y2 * dx) + (4xy + 3y2) * dy = 0

Reorder the terms:

(2dxy2 + 2dx2) + (4xy + 3y2) * dy = 0

(2dxy2 + 2dx2) + (4xy + 3y2) * dy = 0

Reorder the terms for easier multiplication:

2dxy2 + 2dx2 + dy(4xy + 3y2) = 0

2dxy2 + 2dx2 + (4xy * dy + 3y2 * dy) = 0

2dxy2 + 2dx2 + (4dxy2 + 3dy3) = 0

Reorder the terms:

2dxy2 + 4dxy2 + 2dx2 + 3dy3 = 0

Combine like terms: 2dxy2 + 4dxy2 = 6dxy2

6dxy2 + 2dx2 + 3dy3 = 0

Solving

6dxy2 + 2dx2 + 3dy3 = 0

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Factor out the Greatest Common Factor (GCF), 'd'.

d(6xy2 + 2x2 + 3y3) = 0

Subproblem 1

Set the factor 'd' equal to zero and attempt to solve:

Simplifying

d = 0

Solving

d = 0

Move all terms containing d to the left, all other terms to the right.

Simplifying

d = 0

Answered by brainlyehsanul
1

Solution :

Value of y is 25

x + y = 69

x + 25 = 69

x = 69 – 25

x = 44.

Hence :

  • The value of x is 44.
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