Question

how much electrons are moving through a conductor when when ampere of electric current is indicated in it ​

Answer 1

Explanation:

Q = n e

$1 = n \times 1.6 { \times 10}^{ - 19}$

$n = \frac{1}{1.6 { \times 10}^{ - 19} }$

$n = 6.25 \times {10}^{18}$

hope this would help you!!