How much energy is released or absorbed when one gram of steam at hundred degree celsius truns to ice at zero degree celsius?
Answers
Answered by
4
It will be a three step process.
(1)Steam will convert into water at 100°C, latent heat of vapourization of water will be released (mL).
(2)Water will cool down to 0°C, heat released will be (ms∆t).
(3) Water at 0°C will convert into ice at 0°C, latent heat of fusion of water will be released (mL).
m is mass of steam. All three steps are cooling down steps thus heat will be released therefore heat released in above three steps will add up to give total heat released.
Hope it will be helpful.
(1)Steam will convert into water at 100°C, latent heat of vapourization of water will be released (mL).
(2)Water will cool down to 0°C, heat released will be (ms∆t).
(3) Water at 0°C will convert into ice at 0°C, latent heat of fusion of water will be released (mL).
m is mass of steam. All three steps are cooling down steps thus heat will be released therefore heat released in above three steps will add up to give total heat released.
Hope it will be helpful.
Similar questions