Question

how much energy will be needed to convert 2.5 moles of Li to gaseous state to form Li+ ?​

Answer 1

Around

8.64

⋅

10

−

19

J

=

5.40

e

V

Explanation:

The ionization energy tells us that for 1 mole of gaseous lithium,

520

k

J

of energy is needed to ionise each atom.

We also know that 1 mole contains

6.02

⋅

10

23

atoms (to

3

s.f.)

So, 1 atom =

1

6.02

⋅

10

23

=

6.02

⋅

10

−

23

m

o

l

520

k

J

=

520000

J

=

5.2

⋅

10

5

J

(

5.2

⋅

10

5

)

(

6.02

⋅

10

−

23

)

=

8.64

⋅

10

−

19

J

8.64

⋅

10

−

19

1.60

⋅

10

−

19

=

5.40

e

V