Question

how much energy will be released if 200 grams of water at 30 degree celsius is converted into ice at zero degree celsius​

Answer 1

Answer:

1. Q=ml + msdt where
2. l = 80 Cal/gm , dt = change in temp, s = specific heat of water .i.e is 1 Cal/gm/Celsius

Explanation:

1. Q= 200× 80 + 200×1×30
2. Q= 16000 + 6000
3. Q= 22000 Cal/gm

Answer 2

Answer:

Explanation:if you don't understand the attach solution then reply again