Question

How much force is applied to stop a cricket ball of mas 200 g moving with a velocity 2m/s in 10s?​

Answer 1

Answer:

0.04 N

Explanation:

a = $\frac{v - u}{t}$

a = $\frac{2 - 0}{10}$

a = $\frac{2}{10}$

a = 0.2 m/s^2

m = 200g = 0.2kg

F = ma

F = 0.2 x 0.2

F = 0.04 N