Question

How much force is exerted on a 3 kg object accelerates from 12 m/s to rest in 5.5 seconds

Answer 1

a= 12÷5.5=2.1818m/S*2
F=M×A=3×2.1818=6.5454N

Answer 2

Given:

Mass of object = 3kg

Initial velocity of object = 12 m/s

Time taken to come at rest = 5.5 seconds

To find:

How much force is exerted on the object?

Solution:

We will first find the acceleration of the object

Given,

initial velocity, u = 12 m/s

final velocity, v = 0 m/s

time taken, t = 5.5 seconds

acceleration, a = $\frac{v-u}{t}$

a = $\frac{12-0}{5.5}$

a = 2.18 m/$sec^2$

Now we know that force is equal to the product of mass and acceleration, therefore

Force = mass x acceleration

F = 3 x 2.18

F = 6.54 N

Therefore, the force exerted on the object will be 6.54 N.