Question

How much force is the force of friction between a wooden block of mass 5 kg and the horizontal marble floor? The coefficient of friction between wood and marble

Answer 1

Answer:

Component of force F horizontally forward = F Cos B

vertical component of F, upwards = F sin B

Normal reaction N of the floor on the block = N = m g - F Sin B,  as N+ F Sin B is balanced by N.  There is no movement of the block in the vertical direction.

kinetic friction on the block = μ N = μ (m g - F Sin B)  acting backwards.

net force on the block M = F Cos B - μ (m g - F Sin B)

acceleration of hte block in the forward direction :

            force / mass = [ F Cos B - μ (m g - F Sin B) ] /M

Answer 2

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${\huge{\purple{ answer :}}}$

Component of force F horizontally forward = F Cos B

vertical component of F, upwards = F sin B

Normal reaction N of the floor on the block = N = m g - F Sin B,  as N+ F Sin B is balanced by N.  There is no movement of the block in the vertical direction.

kinetic friction on the block = μ N = μ (m g - F Sin B)  acting backwards.

net force on the block M = F Cos B - μ (m g - F Sin B)

acceleration of hte block in the forward direction :

            force / mass = [ F Cos B - μ (m g - F Sin B) ] /M

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