Question

A ladder is placed against a wall such that it's foot is at a distance of 2.5 m from the wall and its top reaches a window 6 m above the ground. Find the length of the ladder



Don't copy it from ncert textbook give me the detailed solution

Answer 1

It's a right angle triangle ....

so,

the length of the ladder is √[(2.5)^2 + (6)^2]

= √[ 42.25]^2

= 6.5 m

Answer 2

${\huge{\bold{\mathbb{\red{Hëy \:Saloni..}}}}}$

Here is the Solution..

${\bold{\boxed{Step\:By\:Step\: Explanation}}}$

.

.

.

.

I Hope This Will Help You ❣️^_^ ^_^