Question

how much hcl is required to decompose 50g of limestone​

Answer 1

Step 1: Write the balanced chemical equation for the reaction of HCl with limestone (calcium carbonate), CaCO3

2HCl + CaCO3 → CaCl2 + CO2 + H2O

Step 2: Now that our equation is properly balanced, we see that for every mole calcium carbonate, we need 2 moles of hydrochloric acid.

The molar mass of CaCO3 is 100.087 g/mol, so

mol CaCO3 = (50 g)/(100.087 g/mol) = 0.4996 mol CaCO3

Again, we have a 2:1 ratio, so

(0.4996 mol CaCO3)x(2 mol HCl per mol CaCO3) = 1.0 mol HCl

Answer 2

36.5 HCL is required to decompose 50g of lime stone

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