How much heat energy (in megajoules) is needed to convert 7 kilograms of ice at –9°C to water at 0°C?
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2.48 mj heat energy is needed to convert 7 kilograms of ixe at -9°c to water at 0°c
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"As per the question, we have to calculate the total amount of heat energy that will be q
So, q = M * S * T
Q = 7 * 4.2 * 1000 * 9 joules
Q = 264600 Joules
Q = 264600 * 10^-6 Mega Joules
Hence, q = .2646 megajoules of heat energy is used for the conversion of ice at -9 degrees.
"
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