Question

How much heat energy is necessary to raise the temperature of 5 kg of water from 20°C to 100°C.

Answer 1

Answer:

Hello friends

Hope it is helpful to you

Your Answer is given below :-

For water, the value of . C is 4.186Jg°C.So,Q=750×4.186×85=266858J=266.858kJDT = temperature difference =100-20=80 0C. Answer is 266.858kj1 calorie = 4.18 Joules. Thus 4180 Joules of energy of heats required for a Kilogram of water through just one degree centigrade.

Answer 2

Answer:

Explanation:

. Given: Mass (m) = 5 kg

Temp. difference (∆T) = 100 - 20 = 80°C

Specific heat capacity (c) = 1 kcal/kg°C

To find: Heat energy (Q) = ?

Formula: Q = mc∆T

Solution:Q = 5 × 1 × 80

= 400 kcal