Question

how much heat energy is necessary to raise the temperature of 5 kg of water from 20 degree Celsius 100 degree Celsius

Answer 1

Quantity of heat required to raise 5 kg of water from 20 0C  to 1000C is given by the formula:Q=m×c×ΔT(Q is usually used to symbolize that heat required in a case like this.)For water, the value of .C  is 4.186Jg°C.So,Q=750×4.186×85=266858J=266.858kJDT = temperature difference =100-20=80 0C.

Answer is  266.858kj1 calorie = 4.18 Joules. Thus 4180 Joules of energy of heats required for  a Kilogram of water through just one degree  centigrade. So, we are to save  save energy .

Answer 2

Answer: 400 Kcal

Explanation:

Data : m = 5 , c = 1 kcal/kg ,

Delta T = 100 -20 = 80 Celsius

Q = m×c×delta T

= 5 ×1 × 80

= 400

Hence heat required is 400 kcal

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