Question

How much heat energy is necessary to raise the temperature of 6 kg of water from 40 C to 100 C

Answer 1

How much heat energy is necessary to raise the temperature of 6 kg of water from 40 C to 100 C?

=> 300 kcal

Step by step explanation :

Given :

m = 5 kg

c = 1 kcal/ kg°C

∆T ( Change in temperature ) = 100 - 40 = 60°C

Energy to be supplied to water = Energy gained by water

= mass of water × specific heat of water × change in temperature

= mc∆t

= 5 × 60° C

= 300 kcal

Hence,Heat energy necessary to raise temperature of water = 300 kcal.

Answer 2

Answer : 300 kcal

∆ t = 100 - 40 = 60°

m = 1

c = 5

mc∆t = 1 × 5 × 60

mc∆t = 300 kcal

Answer to the question is 300 kcal

Hope it helps!