How much heat energy will be given off in cooling water of 2.5kg from 85 °c to 35 °c?
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since Q=mc((del)t)
Q=25/10×1×(85-35)
=2.5×50
=125cal
Q=25/10×1×(85-35)
=2.5×50
=125cal
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hope this is beneficial
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