Question

How much heat must be absorbed by 10 grams of ice to melt into water?

Answer 1

Answer:

Let us consider-

Heat supply= Q

mass of water = m = 10gm

latent heat of fusion = h

change in temperature = ∆T

Specific heat of water = C

now…

Q = (m x C x ∆T) + (m x h)

Now since melting of ice doesn’t incur and change is temperature, so ∆T = 0 ,

so, (m x C x ∆T) =0

hence heat required to melt 10gm of ice at 0°C is —->

Q = 10gm x 334 J/gm = 3340 J ………. ans.

(h= 334 J/gm or 334 kJ/kg)

Answer 2

Answer:

,to convert 10g of ice at 0∘C to same amount of water at the same temperature, heat energy required would be 80⋅10=800 calories. So,to convert water at 100∘C to steam at 100∘C heat energy required will be 537⋅10=5370 calories.