how much heat should be supplied to 2g ice at 0°C to convert it to 2g water at 0°C?
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Answered by
2
Answer:
Since the temperature is kept constant the heat required will be just the latent heat of fusion
Q = mL
Where,
Q - heat required
m - mass of the water = 2g
L - latent heat of fusion of water = 333J/g
Q = mL = 2g*333J/g = 666J
If you want in calories you can use
L = 79.5cal/g
Q = 2*79.5 = 159cal
Answered by
1
answer will be 672 Joule
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