Question

how much heat should be supplied to convert ice of mass 250 g at 0 degree Celsius into water at 20 degree Celsius?​

Answer 1

Answer:

250 at 0d is 0

Explanation:

250*20=105

Answer 2

Answer:

Hey dear here is your answer!!!!!

Explanation:

Firstly we need to convert the ice form of water into water form through latent heat of fusion for ice which is 384J/gram. So to convert 250g of ice into water we need 384 x 20 = 7680J.

Now, to raise the temperature of water up to 20°C we need to provide it some heat.

Specific heat capacity of water is 4.184J/g/°C.

To heat 250g water up to 20°C we need 250 x 20 x 4.184 = 20920J.

Total energy needed = 7680 + 20920 = 28600J.

❣️⭐ Hope it helps u dear...⭐⭐❣️❣️

Thank You