how much hydrogen will be liberated if 6.5g of zn is added to 1 litre of a hcl acid solution containing 3.65g of hcl per litre
Answers
Zn + 2HCl -> ZnCl2 + H2
According to the above equation, we can say that,
1 mole of Zn reacts with 2 moles of HCl to form 1 mole of H2
this also means, 65g of Zn would react with 2*(36.5)g of HCl
so, 1g of Zn would require-> {2*(36.5)}/65g of HCl
therefore, 6.5g of Zn would require -> [{2*(36.5)}/65]*6.5g of HCl
= 7.3g of HCl
However, as only 3.65g of HCl is present, the reaction will end soon before entire Zn is consumed. So, here HCl would be the limiting factor.
so,
7.3g of HCl would require-> 6.5g of Zn
1g of HCl would require -> 6.5/7.3 g of Zn
3.65g of HCl would require-> (6.5/7.3)* 3.65 = 3.25g of Zn
This means that a certain quantity of Zinc- (6.5-3.25)g = 3.25g would be left unused towards the end of reaction.
Now,
From the equation,
73g of HCl gives -> 2g of H2
1g of HCl would give -> 2/73g of H2
3.65g of HCl would give -> (2/73)*3.65g of H2
= 0.1g of H2
Ans:- 0.1g of H2 is produced 6.5g of Zn reacts with 3.65g/l solution of HCl.
Answer:
Explanation:
Concept:
The chemical element hydrogen is represented by the letter and atomic number
. The lightest element is hydrogen. Under normal circumstances, hydrogen is a gas made up of diatomic molecules with the formula
. It is non-toxic, tasteless, colourless, odourless, and highly combustible. In the cosmos, hydrogen is the most prevalent chemical, making up around
% of all ordinary matter. Plasma hydrogen makes up the majority of stars like the Sun. On Earth, hydrogen mostly takes the form of molecules like water and organic substances. Each atom of hydrogen's most prevalent isotope,
, has one proton, one electron, and no neutrons.
Given:
of
is added to
litre of a
acid solution containing
of
per litre
Find:
We have to find the how much hydrogen will be liberated if of
is added to
litre of a
acid solution containing
of
per litre
Solution:
Given that of
is added to
litre of a
acid solution containing
of
per litre
Equation for the aforementioned reaction is:
The aforementioned equation allows us to state that,
2 moles of and
mole of
combine to make
mole of
.
Additionally, this implies that of zinc would react with
of
.
So, of
would need ->
of
Therefore, would be needed for
of
. 6.5 grammes of
of
.
However, because there are just of
in the mixture, the reaction won't last long before all of the
is used up.
would thus be the limiting factor in this case
so,
of
would be needed to make
of
.
would need to be
for
of
.
of
would be needed to equal
of
This implies that a specific amount of Zinc- would be left behind at the conclusion of the reaction.
Now,
The equation yields
grammes of hydrogen gas are produced from
grammes of
of
would result from
of
of
would result in the following equation:
of
=
of
.
Hence g of Zn react with a
g/l solution of HCl to produce
g of H2.
#SPJ2