Question

sinA+cosA=mand secA+cosecA = n show that n(m*m-1)=2m

Answer 1

ANSWER
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LHS : n(m2 - 1)

= secA +cosecA [ (sinA +cosA)2 - 1]

= secA + cosecA [ sin2A + cos2A + 2 sinA .cosA -1]

= secA +cosecA [ 1 +2 sinA . cosA -1] [sin2A +cos2A =1]

= secA +cosecA [ 2sinA cosA]

= 2 secA sinA cosA + 2 cosecA sinA cosA

= 2sinA + 2 cosA [secA*cosA=1 and cosecA*sinA=1]

= 2(sinA +cosA)

= 2 m [sinA +cosA =m]

= RHS

Answer 2

here is the answer

of the question