How much iron is needed to make a rod of length 90 cm and diameter 1.4 cm?
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Answered by
129
length of rod , l = 90 cm
diameter of rod , d = 1.4 cm
so, radius of rod , r = 1.4/2 = 0.7 cm
volume of rod = πr²l
= 22/7 × 0.7 × 0.7 × 90
= 22 × 0.1 × 0.7 × 90
= 22 × 0.7 × 9
= 198 × 0.7
= 138.6 cm³
hence, 138.6 cm³ iron is needed to make a rod of length 90 cm and diameter 1.4 cm.
diameter of rod , d = 1.4 cm
so, radius of rod , r = 1.4/2 = 0.7 cm
volume of rod = πr²l
= 22/7 × 0.7 × 0.7 × 90
= 22 × 0.1 × 0.7 × 90
= 22 × 0.7 × 9
= 198 × 0.7
= 138.6 cm³
hence, 138.6 cm³ iron is needed to make a rod of length 90 cm and diameter 1.4 cm.
Answered by
55
Hi ,
Dimensions of the rod ( cylinder shape ):
height ( h ) = 90 cm
diameter ( d ) = 1.4 cm
radius ( r ) = d/2 = 1.4/2 = 0.7 cm
Quantity of iron needed to make the rod
= volume of the rod
= πr²h
= ( 22/7 ) × ( 0.7 )² × 90
= 138.6 cm³
I hope this helps you.
: )
Dimensions of the rod ( cylinder shape ):
height ( h ) = 90 cm
diameter ( d ) = 1.4 cm
radius ( r ) = d/2 = 1.4/2 = 0.7 cm
Quantity of iron needed to make the rod
= volume of the rod
= πr²h
= ( 22/7 ) × ( 0.7 )² × 90
= 138.6 cm³
I hope this helps you.
: )
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