How much is 3a²-5ab+7b²+3 greater than 2a²+2ab+5b ?
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16
3a²-5ab+7b²+3 - ( 2a²+2ab+5b)
= 3a²-5ab+7b²+3- 2a²-2ab-5b
= a² -7ab +7b²-5b+3
= 3a²-5ab+7b²+3- 2a²-2ab-5b
= a² -7ab +7b²-5b+3
nikhilchhokar89:
Bakhwas
Answered by
9
3a²-5ab+7b²+3 -(2a²+2ab+5b)
=a² -7ab +7b² -5b +3
therefore it is a² -7ab +7b² -5b +3 greater
=a² -7ab +7b² -5b +3
therefore it is a² -7ab +7b² -5b +3 greater
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