Math, asked by VivPhata, 30 days ago

how much is 4+a‐2a²+a³greater than 6‐5a+7a²+2a³​

Answers

Answered by ajajit9217
1

Answer:

4+a-2a^{2}+a^{3} is2+6a-9a^{2}-a^{3} greater than 6-5a+7a^{2}+2a^{3}

Step-by-step explanation:

We subtract 6-5a+7a^{2}+2a^{3} from 4+a-2a^{2}+a^{3}

(4+a-2a^{2}+a^{3})-(6-5a+7a^{2}+2a^{3})

=4+a-2a^{2}+a^{3}-6+5a-7a^{2}-2a^{3}

=4-6+a+5a-2a^{2}-7a^{2}+a^{3}-2a^{3}

=-2+6a-9a^{2}-a^{3}

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