Math, asked by dange4269, 4 months ago

how much is a²+2ab+b² more than a²-2ab+b²​

Answers

Answered by samsk1912
0

We can simply subtract the smaller one from the bigger and we will get our answer that is :-

2a^2 - 3b^2  +ab - (a^2 -+ 3b^2 - 2ab)

2a^2 - 3b^2 +ab - a^2 - 3b^2 +2ab

2a^2 - a^2 -3b^2 -3b^2 +ab +2ab

a^2 - 6b^2 + 3ab

Hence a^2 - 2ab+3b^2 is less than 2a^2 - 3b^2 + ab by a^2 - 6b^2 + 3ab

Answered by saumyabiju
0

Answer:

-4ab

Step-by-step explanation:

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