How much is the angular distance between the Tropic of Cancer and Tropic of Capricorn?
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Answer:
- Both the tropics of Capricorn and Cancer are 23.43692 degrees from the equator. So the angular distance between the two is 46.8738 degrees (2 x 23.437) of latitude. One nautical mile is defined as one minute of latitude.
Answered by
4
Explanation:
Both the tropics of Capricorn and Cancer are 23.43692 degrees from the equator. So the angular distance between the two is 46.8738 degrees (2 x 23.437) of latitude.
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