Question

How much is the equivalent resistance of combination of resistors, when three resistors of values 3Ω, 6Ω, 9Ω are connected in parallel​

Answer 1

concept:-

in parallel connection:-

$\sf\dfrac{1}{R}$ = $\sf\dfrac{1}{R1}$ + $\sf\dfrac{1}{R2}$ + $\sf\dfrac{1}{R3}$ ........

solution:-

$\sf\dfrac{1}{R}$ = $\sf\dfrac{1}{3}$ + $\sf\dfrac{1}{6}$ + $\sf\dfrac{1}{9}$ = $\sf\dfrac{11}{18}$

R = $\sf\dfrac{18}{11}$ Ω