How much is the gravitational force that keeps an
artificial satellite of mass 3500 kg in orbit around the
Earth at an altitude of 4200 km
Answers
Answered by
2
Answer:
Force=GMm/d^2,G=6.674×10^-11N-kg^2/m^2
mass of earth(M)=6×10^24kg
mass of satellite (m)=3500kg
distance between earth and satellite =4200km
force between earth and satellite(F)=6.674×10^-11×6×10^24×3500/(4200)^
=7.945×10^9
=7.95×10^9 N
Answered by
1
Answer:
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7.945×10^9 is your answer
Explanation:
mass of earth(M)=6×10^24kg
mass of satellite (m)=3500kg
distance between earth and satellite =4200km
force between earth and satellite(F)=6.674×10^-11×6×10^24×3500/(4200)^
=7.945×10^9
=7.95×10^9 N
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