Question

how much is y^4-12y^2+y+14 greater than 17y^3+34y^2-51y+68​

Answer 1

Given: Two terms  y^4-12y^2+y+14 and 17y^3+34y^2-51y+68​

To find: How much is y⁴ - 12y² +y+14 greater than 17y³ + 34y² -51y + 68 ?

Solution:

• Now we have given two terms.

• We have to subtract 17y³ + 34y² -51y + 68 from y⁴ - 12y² + y + 14

• Subtracting the term, we get:

                    y⁴ - 12y² + y + 14 - ( 17y³ + 34y² - 51y + 68 )

• Solving it, we get:

                    y⁴ -12y² + y + 14 - 17y³ - 34y² + 51y - 68

• Taking like terms together, we get:

                    y⁴ -12y² -34y² +y +51y +14-68- 17y³

                    y⁴ - 46y² + 52y - 17y³ - 54

                    y⁴ - 17y³ - 46y² + 52y - 54

Answer:

         So after subtraction the answer comes out to be  y⁴ - 17y³ - 46y² + 52y - 54