Question

how much lager is 8x^2-9y^2 than 3^2-2y^2

Answer 1

Answer:

5x^2 -7y^2

Step-by-step explanation:

The value by which  $(8x^2 - 9y^2)$ is larger than $(3x^2 - 2y^2)$ is as follows:-

$(8x^2 - 9y^2) - (3x^2 - 2y^2)\\= 8x^2 - 9y^2 - 3x^2 + 2y^2\\= 5x^2 -7y^2$

Answer 2

Step-by-step explanation:

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