Question

How much magnesium sulphide can be obtained from 2g of mg and 2g of s by the reaction mg+s gives mg?

Answer 1

mg +.s = mgs

2 g. 2 g

Mg moles 2/24

moles of S 2/32 Limiting reagent

1 mole of sulphur gives 1 mole sulphide

1 mole MgS mass =56gm