Question

How much mass of CH4 would react with 96 g of oxygen

Answer 1

Answer:

Chemical Equation -:

CH4 + 2O2 ---------> CO2 + 2H20

So we can see that 1 mole of CH4 reacts witg 2 moles of O2,

now, we will find the no. of moles of O2 that we have,

No of moles = Given mass/ molar mass

No of moles of O2 = 96g / 32g

(molar mass if O2 = 2 × atomic mass of O = 2 × 16 = 32)

No of moles of O2 = 3 moles

Now, lets go back to the equation.

We saw that 2 moles of O2 react with 1 mole of CH4,

So, 1 mole of O2 would react with 1/2 moles of CH4

(Just using unitary method:)

Now, 3 moles would react with 1/2 × 3 moles of CH4.

So, moles of CH4 = 3/2

We know,

No. of moles = Given mass/ molar mass

so, No. of moles of CH4 = Given mass/16 g

(since, molar mass of CH4 = 12+4×1= 16g )

So, 3/2 = mass of CH4 / 16

Mass of CH4 = 3/2 × 16 = 24 g

Hence, 96 g of O2 reacts witg 24 g of CH4.

I hope you understood :)

Answer 2

Answer:

48 Gram

Explanation:

CH4 + 2O2 = CO2 + 2H20

1mol + 2mol =  1mol + 2mol

16gram + 32gram = 44gram + 36gram

32 gram Oxygen needs 16 gram CH4

96 gram oxygen needs 16/32 x 96 gram CH4

Hence, 96 gram Oxygen needs 48 gram CH4