Question

How much metal sheet is required to make a closed cylindrical tank of height 50cm and diameter of base 112cm ? Find the area of the metal sheet in sq meter ?

Answer 1

The area of the metal sheet is $\mathbf{37312 \ cm^{2}}$.

Step-by-step explanation:

• Given data

        Height of cylinder (H) = 50 cm

        Diameter of base (D) = 112 cm

        So

        Radius of base (R) = 56 cm

         $\mathbf{Value \ of \ pi \ (\pi )=\frac{22}{7}}$

• We know that total surface area of cylinder is

        $\mathbf{T.S.A \ of \ cylinder=2\pi R(R+H)}$

        $\mathbf{T.S.A \ of \ cylinder=2\times \frac{22}{7} \times 56\times (56+50)}$

        $\mathbf{T.S.A \ of \ cylinder=2\times 22 \times 8\times 106}$

        $\mathbf{T.S.A \ of \ cylinder=37312 \ cm^{2}}$

       

Answer 2

Answer:

Total surface area of metal sheet required is 3.72 sq meter

Step-by-step explanation:

Given as :

The height of cylindrical tank to be made = h = 50 cm

The diameter of base of tank = d = 112 cm

radius of base = r = $\dfrac{d}{2}$

i.e  r = $\dfrac{112}{2}$  = 56 cm

The quantity of metal sheet required = Total surface area of cylindrical tank

According to question

∵ Total surface area of cylindrical tank = $2 \times \Pi \times radius\times height$ + $2 \times \Pi \times radius$²

Or, A = $2 \times \ 3.14 \times r\times h$ + $2 \times \ 3.14 \times r$²

Or, A = 2 × 3.14 × 56 × 50  + 2 × 3.14 × 56²

or, A = 17584 cm²  + 19694.08 cm²

∴   Total surface area = A = 37278.08 cm²  = 3.72 m²

Hence, Total surface area of metal sheet required is 3.72 sq meter Answer