How much Metal sheet is required to make an open cylindrical tank of radius 4.2m and 15m?
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Answered by
3
we have
r= 4.2,m.
. h =15m
we know
total surface area of cylinder=
2πr(r+h) -πr^2. ( open with top)
=π[2×4.2(4.2+15)-4.2^2]
=π[8.4(19.2) -17.64]
= π[161.28-17.64]
=π[143.64]
=22/7[143.64]
= 45.44m^2
hence 45.44m^2 metal sheet is required
r= 4.2,m.
. h =15m
we know
total surface area of cylinder=
2πr(r+h) -πr^2. ( open with top)
=π[2×4.2(4.2+15)-4.2^2]
=π[8.4(19.2) -17.64]
= π[161.28-17.64]
=π[143.64]
=22/7[143.64]
= 45.44m^2
hence 45.44m^2 metal sheet is required
Answered by
0
Answer:
Trigonometry, the branch of mathematics concerned with specific functions of angles and their application to calculations. There are six functions of an angle commonly used in trigonometry. Their names and abbreviations are sine (sin), cosine (cos), tangent (tan), cotangent (cot), secant (sec), and cosecant (csc).
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