Question

how much mole will contains in 1.5 g of acetic acid

Answer 1

acetic acid(ch3cooh) have molecular mass 60

so 60gm of acetic acid contains 1 mole
so 1gm of acetic acid will contain 1/60 me
hence 1.5gm of acetic acid will contain 1/60*1.5
=1/40 mole

Answer 2

gram molecular mass of acetic acid(CH3COOH) : 60
mole = mass/g.m.m
mole = 1.5/60
=0.025