Question

how much momentum mass will a temple of 10kg transfer to the floor if it fall from the height of the 80 cm then it required acceleration to be 10 MS

Answer 1

Mass of the temple, m = 10 kg
Distance covered by the temple, s = 80 cm = 0.8 m
Acceleration in the downward direction, a = 10 m/s2
Initial velocity of the temple, u = 0
Final velocity of the temple(when it was about to hit the floor) = v
According to the third equation of motion: 
${v} ^{2} = {u}^{2} + 2as$
u=0
v = 4 m/s 
Hence, the momentum with which the temple hits the floor is 
= mv = 10 × 4 = 40 kg m s−1