Question

how much momentum will a bell of mass 10 kg transfer to the floor if it falls from a height of 80 cm?

Answer 1

u= 0
a=10m/s^2
s= 0.8m
v=?

2as= v^2-u^2
v^2= 20x0.8
v^2= 16
v= 4

Momentum = mv= 10x4= 40kgm/s
So the momentum transferred to the floor is 40kgm/s

Answer 2

$\bf{\underline{\underline{Answer:}}}$

$\bf{\therefore40 \:kg\: m\: {s}^{-1}}$

$\bf{\underline {Given:}}$

• Mass of the dummbell, m = 10 kg

• Distance attain by the dummbell, s = 80 cm = 0.8 m

• Acceleration in the downward direction, a = 10 m/s²

• Initial velocity of the dummbell, u = 0

$\bf{\underline {To\:find:}}$

• Momentum = ?

$\bf{\underline{\underline{Step\: by\: step \:explanation:}}}$

We know that,

v² = u² + 2 as

v² = 0 + 2 (10) 0.8

v² = 16

v = 4 m/s

Now, we know that,

Momentum, p = Mass × Velocity

= 10 × 4

$= \bf{40 \:kg\: m{s}^{-1}}$